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solong [7]
3 years ago
5

Can a graph be linear with a outlier

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

yes it can be.

Step-by-step explanation:

jrjrjekekekdkdkdkdmdmdmrmmedmdmdmdmdmdm

You might be interested in
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
I would like step by step explanation
Nezavi [6.7K]

Answer:

the number is 87

Step-by-step explanation:

the photo contains step by step

3 0
3 years ago
Read 2 more answers
What is the answer to the equation 6x-x/x+1
avanturin [10]

Answer:

5x/x+1

Step-by-step explanation:

Numerator: 6x minus an x equals 5x.

Denominator: Since x and 1 are not like terms, they can't be combined. You just leave them as they were.

Hope this helps!

6 0
3 years ago
$10,000 at an annual rate of 7%, compounded semi-annually, for 2 years
forsale [732]

Answer:

\$13,107.96

Step-by-step explanation:

Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.

Therefore, we can set up the following equation to find the new balance after 2 years:

\text{New balanace}=10,000\text{ (old balance)}\cdot 1.07\cdot 1.07\cdot 1.07\cdot 1.07,\\\text{New balanace}=10,000\cdot 1.07^4=\boxed{\$13,107.96}

8 0
3 years ago
Ricky withdrew a total of $175 from his bank account over 5 days. He withdrew the same amount each day. By how much did the amou
kifflom [539]

Answer:

$35

Step-by-step explanation:

175/5 = 35

have a nice day! (maybe get this double checked in case I did it wrong :D)

8 0
2 years ago
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