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Novosadov [1.4K]
3 years ago
6

1. How many more monthly payments are made for a five-year loan than for a three-year loan?​

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

Answer: There are 24 more payments made.

Step-by-step explanation:

In a 5 year loan there is 60 months

In a 3 year loan there is 36 months.

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Mr. Vedra deposited $1,200 in a certificate of deposit (CD) at an interest rate of 5.5%. He earned $198 in simple interest. How
UkoKoshka [18]

Answer: 3 (include unit in your answer, as it was not mentioned in question)

Step-by-step explanation:

5.5% of 1200 =

1200/100 x 5.5 = 66

Time = 198/66 = 3

put the units in, if its 5.5% per annum or months or days, since it wasnt mentioned in the question :)

4 0
3 years ago
Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
Write the average of y numbers. Is 22 the numbers 20, 17, 24, 18, 29 and x. find x
Elena L [17]
22 is the average of the numbers 20,17,24,18,29, and x is what I guess the qusetion is

count them
6 numbers

(20+17+24+18+29+x)/6=22
(108+x)/6=22
times both sides by6 to clear fraction
108+x=132
minus 108 from both sides
x=24
3 0
3 years ago
What is 100,572×135,689
shepuryov [24]

Answer:

13646514108

Step-by-step explanation:

Used calculator.

5 0
3 years ago
Read 2 more answers
All Seasons Plumbing has two service trucks that frequently need repair. If the probability the first truck is available is 0.75
oksano4ka [1.4K]

Answer: There is a probability of 0.05 that there is neither truck is available.

Step-by-step explanation:

Since we have given that

Probability that the first truck is available = 0.75

Probability that the second truck is available = 0.50

Probability that both trucks are available = 0.30

So, probability that either first truck or second truck is available is given by

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.75+0.50-0.30\\\\P(A\cup B)=0.95

We need to find the probability that neither truck is available.

so, P(A∪B)'=1-P(A∪B)

P(A\cup B)'=1-0.95=0.05

Hence, there is a probability of 0.05 that there is neither truck is available.

4 0
4 years ago
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