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3 years ago

3 . 072 > 3 . 2 Choose...

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

The answer is 3.2.

Step-by-step explanation:

cricket20 [7]3 years ago

6 0

Answer:

the statement above is false a

Step-by-step explanation:

3.2 is greater than 3.072

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The expression 2(l + w) is used to calculate the perimeter of a rectangle, where l is length and w is width. If the length is Fr

Art [367]

Answer:

Perimeter = 1 unit

Step-by-step explanation:

$length \ is \ a \ fraction \ 2 \ over \ 3 = \frac{2}{3}\\\\Width \ is \ a \ fraction \ 1 \ over \ 3 = \frac{1}{3}\\\\Perimeter = 2 ( l + w)\\$

$= 2 \times (\frac{2}{3} + \frac{1}{3}) \\\\=2 \times (\frac{3}{3})\\\\= 1 unit$

5 0

2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

0.12x - 1.5= 0.24x - 0.06

Sophie [7]

To solve this equation, lets move all of the variables to one side of the equation and the constants to the other.

0.12x - 1.5 = 0.24x - 0.06

Subtract 0.12x from both sides of the equation

-1.5 = 0.12x - 0.06

Add 0.06 to both sides of the equation

-1.44 = 0.12x

Divide both sides by 0.12 to isolate x

x = -12

5 0

3 years ago

706,421 rounded to the neares thousand

ella [17]

706,421 rounded to the nearest thousand is 706,000 because the 421 is less than 500 so the 6 would remain a 6.

3 0

3 years ago

james was diving in the ocean. he decided to ascend 11 feet to be able to see the coral better. he was then at -13 feet from the

vesna_86 [32]

Answer: -1 because - 13 - 11 will = -1

5 0

2 years ago