Here is a circle. Points A, B, C, and D are drawn, as

Mr. Thompson's sixth-grade class is competing in the school field day. There are 16 boys and 12 girls in his class. He divided t

slamgirl [31]

There are 3 girls on each team and 4 boys on each team.

4 0

4 years ago

PLEASE HELP ME THIS QUESTION! I'LL VOTE YOU BRAINLETS!

d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

Let's add the amounts earned together to find his total earnings. This is 60 + 84 + 72 + 96 + 48 = $360. If he had $218 left over the skis cost 360 - 218 = $142.

7 0

3 years ago

Find the conjugate and product of 2-i5

WITCHER [35]

Answer: $2+i5,\ 29$

Step-by-step explanation:

Given

Complex number is $2-i5$

Its conjugate is obtained by changing the sign of the original number i.e. $2+i5$

The product of the two numbers is

$\Rightarrow (2-i5)(2+i5)=2^2-(5i)^2\quad \quad [(x+y)(x-y)=x^2-y^2]\\\\\Rightarrow (2-i5)(2+i5)=4-25i^2\\\\\Rightarrow (2-i5)(2+i5)=4+25=29$

3 0

3 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago

A factory sells backpacks for $35 each. The cost to make 1 backpack is $15. In addition to the cost of making backpacks, the fac

Otrada [13]

Answer:9400 backpacks

$\geq$ Step-by-step explanation

since the number of packs to be sold in a is represented by x,

selling price for 1 week = 35x

cost price for 1 week = 15x

profit = 35x-15x = 20x

additional cost of production = 11,000

this implies that 20x - 11,000 $\geq$ 7800

20x - 11,000 $\geq$ 7,800

20x $\geq$ 7800+ 11000

20x $\geq$ 18,800

x $\geq$ 18800/2

x $\geq$ 9,400

at least 9,400 packs have to be sold each week to make a profit of $7800

7 0

3 years ago