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Andre45 [30]
3 years ago
14

Bus A leaves the station every 30 mins bus b leaves the station every 20 mins at 10 am both buses leave the station together wor

k out the next time both buses leave at the same time
Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer: 11am

Step-by-step explanation:

To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:

20 = 20, 40, 60, 80, 100

30 = 30, 60, 90, 120, 150.

Here, the lowest common multiple is 60.

Therefore, we add 60 minutes to 10am. This will be:

= 10am + 1 hour

= 11 am

The next time that both buses leave at the same time would be 11am

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Quadrilateral ABCD has vertices at A(-2, -4), B(1, -1), C(-2, 2) and D(-5, -1). What is the name of the figure?
dimaraw [331]

Answer:

a square

Step-by-step explanation:

bc if u plot them on a graph, you get a rhombus but when you turn the page, you also get a square. it said under the rhombus, not a square, so we cross that one out and we hv the res. all the sides are equal so the only answer left is a square

hope it helped xx

4 0
3 years ago
Skylar mowed 16 lawns in 12 hours. What was her rate of mowing in lawns per hour?
erik [133]
16 / 12 = 1.3333
Answer: she mowed 1 1/3 lawns per hour.
8 0
3 years ago
Whats the Area? how do i find it? In these specific questions?
just olya [345]
The formula for finding the area of a square is:
{s}^{2}

The formula for finding the area of a triangle is:
\frac{1}{2} bh

So for the square the area would be:
{2x}^{2} \times  {2x}^{2}  =  {4x}^{2}

The area for the triangle would be:

\frac{1}{2}  {2c}^{3}  \times  4c =  {4c}^{2}
7 0
3 years ago
Lenny Lendee purchased a snowblower for $199.95. He paid 25% down and agreed to pay $14.99 for 12 months.
Ganezh [65]
$199.95 x 25% = $199.95 x .25 = $49.9875 ~ $49.99
$199.95 - 49.99 = $149.96 (actual balance) If Lenny pay $14.99 for 12 months the total payment would be: $14.99 x 12 =$179.88
Lenny would have paid an additional amount of $29.92 ($179.88 - 149.96) after making the final payment.

I hope this helps since you did not mention what you were calculating, so I include everything that can be done to this problem.
8 0
3 years ago
Read 2 more answers
4th term of an arithmetic sequence is 23 and its 11th term is 65, what is its common difference​
Rudik [331]

Answer:

d = 6

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₄ = 23 and a₁₁ = 65 , then

a₁ + 3d = 23 → (1)

a₁ + 10d = 65 → (2)

Subtract (1) from (2) term by term to eliminate a₁

10d - 3d = 65 - 23

7d = 42 ( divide both sides by 7 )

d = 6

5 0
3 years ago
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