Answer: -x/2 + 1
Step-by-step explanation:
write t in terms of x
x = 2t
t = x/2
substitute t in y
y = 1 - t
y = 1 - x/2 or -x/2 + 1
Answer:
46
Step-by-step explanation: .23 (200) = 46
Answer:
ok so you see the equation at the top... you are going to "plug in" the number in the "in" row to get the "out number
Step-by-step explanation:
example
in: 4
-2(-4)+1
8+1
9
so for the out row under -4 you would put 9
-2(-3)+1
6+1
7
so for the out row under 3 you would put 7
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
2,455
Step-by-step explanation:
Use PEMDAS to solve
First multiply 50x50, which is 2,500
50 x 50 + 60 - 105 becomes
2,500 + 60 - 105
Now to the addition or subtraction from left to right
2,560 - 105
2,455
