3 years ago

a pyramid with a square base that is 9 cm on a side has a height of 10 cm the volume of the pyramid is

1 answer:

4 0

$\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh~~
\begin{cases}
B=area~of\\
\qquad its~base\\
h=height\\[-0.5em]
\hrulefill\\
B=\stackrel{9\times 9}{81}\\
h=10
\end{cases}\implies V=\cfrac{1}{3}(81)(10)\implies V=270$

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2. Find the value of <img src="https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B1728%7D%20%2B%20100%20%5Csqrt%5B4%5D%7B81%7D%20-%20%286

Taya2010 [7]

Answer:

(b) 0

Step-by-step explanation:

Assuming a typo in the last term:

5 (1728)^(1/3) + 100(81)^(1/4) - ( 6(10)^(1/2) )^2

=5(12) + 100(3) -36(10)

=60+300-360

5 0

3 years ago

Read 2 more answers

A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the p

motikmotik

x = 26 m is the width of the pool, length: 29+4 = 33 m.

<u>Step-by-step explanation:</u>

We have A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool.

Let the width of the pool = x

Then the length will = (x+4) ,over all dimensions will be (x+6) by (x+6+4) or (x+10)

Total area - pool area = 372

$(x+10)*(x+6) - x(x+4) = 372\\x^{2}+16x+60-x^{2}-4x = 372\\12x+60 = 372\\12x = 372-60\\12x = 312\\x = 26$