Answer: lemme solve it ty
Step-by-step explanation:
hi
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
a. 12.8 cm b. 3.125
Step-by-step explanation:
To find any scale drawing use a proportion with one unit of values on the top and the other on the bottom. For example 8cm/5km = x/8km. So you would multiply 8 cm and 8 km and then divide by 5 to get 12.8 cm. For the second question plug in 5m in the numerator and solve for its denominator.
h=9
A=((a+b)/2)h
234=((32+20)/2)h
234=(52/2)h
234=26h
9=h
