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3 years ago

12

I need some help with these two questions please help!

1 answer:

antoniya [11.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

-10.6*0.5=m+11.7

-5.3=m+11.7

-5.3-11.7=m

-17=m

14.2=2(-5.8+t)

14.2=-11.6+2t

14.2+11.6=2t

25.8=2t

25.8/2=t

12.9=t

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To prove that the triangles are similar by the SSS similarity theorem, which other sides or angles should be used?]

Margarita [4]

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Step-by-step explanation:

Given: In ΔMNO and ΔQRS

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That must be $\overline{MN}$ and $\overline{QR}$

such that $\frac{QR}{MN}=4$

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What is a simple way to tell that -31 is not the slope of this graph?

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3 years ago

3 = t + 11.5 - t

Ray Of Light [21]

Answer:

There are no solutions.

Step-by-step explanation:

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A line passes through point A (14,21). A second point on the line has an x-value that is 125% of the x-value of point A and a y-

seropon [69]

Answer:

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

Step-by-step explanation:

According to the statement, let $A(x,y) = (14,21)$ and $B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A})$ . The equation of the line in point-slope form is defined by the following formula:

$y-y_{A} = m\cdot (x-x_{A})$ (1)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of the point A, dimensionless.

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the slope of the line is defined by:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

If we know that $x_{A} = 14$ and $y_{A} = 21$ , then the equation of the line in point-slope form is:

$x_{B} = 1.25\cdot (14)$

$x_{B} = 17.5$

$y_{B} = 0.75\cdot (21)$

$y_{B} = 15.75$

From (2):

$m = \frac{15.75-21}{17.5-14}$

$m = -\frac{3}{2}$

By (1):

$y-21 = - \frac{3}{2}\cdot (x-14)$

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

5 0

3 years ago