A rationla power is a power in form a/b
remeber these 2 simple rules
1.
2.
![x^\frac{m}{n}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
and the combo of these
![x^\frac{-m}{n}=\frac{1}{\sqrt[n]{x^m}}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7B-m%7D%7Bn%7D%3D%5Cfrac%7B1%7D%7B%5Csqrt%5Bn%5D%7Bx%5Em%7D%7D)
that's all
Answer:
x=4
Step-by-step explanation:
to get rid of the square root on the right you square both sides so
2x+8=x^2
Then bring
2x+8
to the left so you have 0=(x^2)−2x+8
Now you can do the quadratic formula to find the zeroes
In below formula for arithmetic sequence you can fill in a=7 (start), d=2 (interval) and n=35 (nr terms) and you get
17.5(14 + 34*2) = 1435
Confirmed by a brute-force addition: 7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75=1435
Answer:
n=3
9+1=10
n=1
1+1=2
n=5
25+1=26
a odd interger squared is a odd interger so if you add one its even
Hope This Helps!!!
Answer:
The answer to your question is the third histogram
Step-by-step explanation:
What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.
The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.
Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.
The third histogram is correct because all the bars are in agreement with their frequencies.
The last histogram is incorrect, for example, the last frequency is 12, not 3.
