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tatyana61 [14]
3 years ago
11

Factor 30-24x 6(15-12x) 6(5x-4x) x(5-4x) 6(5 - 4x)

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

the second option

Step-by-step explanation:

pretty sure it's the second option

hope this helped ;)

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When records were first kept (t=0), the population of a rural town was 260 people. During the following years, the population gr
Firdavs [7]

Answer:

(a) The population after 15 years is 2678.

(b)Therefore the population P(t) at any time t>0 is

P(t)= 45t+30 {t^{\frac32}}+260

Step-by-step explanation:

Given that,

The population grew at a rate of

P'(t)=45(1+\sqrt t)

Integrating both sides

\int P'(t) dt=\int 45(1+\sqrt t)dt

\Rightarrow \int P'(t) dt=\int (45+45\sqrt t)dt

\Rightarrow \int P'(t) dt=\int 45\ dt+\int 45\sqrt t\ dt

\Rightarrow P(t)= 45t+45\  \frac{t^{\frac12+1}}{\frac12+1}+c              [ c is integration constant]

\Rightarrow P(t)= 45t+45\  \frac{t^{\frac32}}{\frac32}+c

\Rightarrow P(t)= 45t+45\times\frac 23 \times {t^{\frac32}}+c

\Rightarrow P(t)= 45t+30 {t^{\frac32}}+c

When t=0 , P(0)= 260

\therefore 260= 45\times0+30\times {0^{\frac32}}+c

\Rightarrow c=260

\therefore P(t)= 45t+30 {t^{\frac32}}+260

Therefore the population P(t) at any time t>0 is

P(t)= 45t+30 {t^{\frac32}}+260

To find the population after 15 years, we need to plug t=15 in the above expression.

P(15)=( 45\times 15)+30( {15^{\frac32}})+260

         ≈2678

The population after 15 years is 2678.

5 0
3 years ago
Find the domain and range of the function below
natali 33 [55]
X is greater than or equal to 0
y is greater than or equal to 0
6 0
3 years ago
Which property is illustrated? x+y=x+y
Sholpan [36]

Answer:

commutative property of addition

Step-by-step explanation:

commutative property of addition  "a + b = b + a"

7 0
3 years ago
Find the range of the function y=1/2x+3 when the domain is (-2,0,2,4)
Triss [41]

Answer:

{2,3,4,5}

Step-by-step explanation:

Domain is the set of x-values for which the function is defined.

Range is the set of y-values for which the function is defined (set of values corresponding to the set of x-values).

The function is given as  y=\frac{1}{2}x+3

The domain is (-2,0,2,4)

That means, we need to plug-in the 4 numbers given into x of the function and find the 4 corresponding y values (the range).

So, lets do this:

putting x = -2,

y=\frac{1}{2}(-2)+3=2

putting x = 0

y = 3

putting x = 2

y=\frac{1}{2}(2)+3=4

putting x= 4

y=\frac{1}{2}(4)+3=5

Thus, the range is {2,3,4,5}

5 0
3 years ago
Someone please help me on this geometry test
Kamila [148]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
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