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sdas [7]
2 years ago
14

Will's teacher expressed his social studies quiz grade as 17/20. What is his quiz grade expressed as a percent?

Mathematics
1 answer:
lukranit [14]2 years ago
7 0

Answer:

Step-by-step explanation:

0.85%

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Please help! thank you! 10+ points
jonny [76]

Answer:

A (DE = GF)

Step-by-step explanation:

In a isosceles trapezoid, one pair of segments are parallel, and another pair are equivalent in length.

The only choice that fits this criteria is A, where DE equals GF.

7 0
3 years ago
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Is 63 greater than 48.1 or less than<br><br>PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)​
timofeeve [1]

Answer:

63 is greater than 48.1 ...

63 > 48.1

Step-by-step explanation:

63 is greater than 48 remember. So you need to remove the [.1] and focus on the 63 and 48.

<h3>Hope it helps!!</h3><h3><em>Please</em><em> </em><em>mark me as the brainliest</em><em>!</em><em>!</em><em>!</em></h3>

<em>Thanks</em><em>!</em><em>!</em><em>!</em><em>!</em><em>❤</em><em>❣</em><em>❤</em>

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5 0
3 years ago
Read 2 more answers
If a basketball was dropped 32 feet from a second floor of a home, how far would it rebound if it bounciness was
valentina_108 [34]

Answer:

23.68

Step-by-step explanation:

74% = 74/100

\frac{74}{100} · \frac{32}{1} = 23.68

4 0
3 years ago
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In parallelogram WXYZ, what is CY?<br> CY=___ ft
dangina [55]
<span>The correct answer is 11 ft.

Explanation:
The diagonals of a parallelogram bisect each other. This means that the portion marked x+4 is the same length as the portion marked 2x-7; this gives us the equation x+4=2x-7.

Subtract x from each side:
x+4-x=2x-7-x
4=x-7.

Add 7 to both sides:
4+7=x-7+7
11=x</span>
6 0
3 years ago
Read 2 more answers
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
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