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igor_vitrenko [27]
3 years ago
9

Please help me!! I need to know how to do number 1.

Mathematics
1 answer:
zmey [24]3 years ago
3 0
I can't see the paper
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State if the two triangles are congruent. If they are state how you know.<br> Help me
deff fn [24]

Answer:

i think its the last option.

Step-by-step explanation:

its not the first one because they it can be proved using AAS (but that option isnt available)

You can't prove it with SSS or ASA without more info

AAA doesn't exist

theirfore it must be the last option.

3 0
2 years ago
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Match each function formula with the corresponding transformation of the parent function y = 3x
kodGreya [7K]

Answer:

1. y = -3^ x Translated up by 1 unit 2.

2.y = 3^ -x Reflected over the y-axis 3.

3.y = 3 ^x - 2 Translated right by 2 units 4.

4. y = 3 ^x + 1 Translated down by 2 units 5.

5. y = 3^ x + 1 Translated left by 1 unit 6.

6. y = 3 ^x - 2 Reflected over the x-axis

Step-by-step explanation:

7 0
3 years ago
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PLEASE HELP ITS OVERDUE PLEASE I NEED HELP!!
IgorLugansk [536]

Answer:

First question: Choice A

second question:Choice D

Third question: Choice c

Fourth question: Choise b

5th Question: choice b

5 0
3 years ago
A. F(x) &lt; 0 on the interval x &lt; 0.
KiRa [710]

f(x) > 0 - I and II quadrant

f(x) < 0 - III and IV quadrant

Look at the picture.


A. F(x) < 0 on the interval x < 0.     TRUE

B. F (x) > 0 on the interval x <0.      FALSE

C. F (x) < 0 on the interval 0 < x < 1.      TRUE

D. F (x) > 0 on the interval 0 < x < 1.      FALSE

E. F (x) < 0 on the interval 1 < x < 3.     FALSE

F. F (x) > 0 on the interval 1 < x < 3.      TRUE

G. F (x) < 0 on the interval x > 3.     TRUE

H. F (x) > 0 on the interval x > 3.      FALSE    

3 0
3 years ago
An investment banker deposited $50,000 in an account earning a nominal 6% per year compounded continuously. How much was in the
Orlov [11]

Answer:

The amount in the account at the end of three years will be $59,861.

Step-by-step explanation:

The formula to compute the amount at the end of <em>t</em> years, compounded continuously is:

A=P\times e^{t\times i}

Here,

A = Amount at the end

P = Principal amount

i = interest rate

t = number of years.

It is provided that:

P = $50,000

i = 6%

t = 3 years

Compute the amount in the account at the end of three years as follows:

A=P\times e^{t\times i}

   =50000\times e^{(3\times 0.06)}\\=50000\times 1.19722\\=59861

Thus, the amount in the account at the end of three years will be $59,861.

5 0
3 years ago
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