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kupik [55]
3 years ago
9

HELP I ONLY HAVE THESE TWO QUESTIONS LEFT!!!!!!! First, How Many cubic blocks of side length 1/6 inch would it take to fill a cu

be with a side length of 2/6 inch? Second question, How many cubic blocks of the side length 1/7 inch would it take to fill a Rectangular prism with a length, width,and height of 3/7, 1/7, and 3/7 inch, respectively?
Mathematics
2 answers:
earnstyle [38]3 years ago
7 0

Answer:

1. 8 cubic blocks, 2. 9 cubic blocks

Step-by-step explanation:

Ad libitum [116K]3 years ago
3 0

Answer:

1. There are 8 cubic blocks are needed to fill a cube. Explanation in pic

2. 441 cubic blocks will fill the rectangular prism. Explanation in pic

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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In ΔJKL, j = 93 cm, k = 82 cm and l=86 cm. Find the measure of ∠J to the nearest degree.
zhuklara [117]

Answer:

5

Step-by-step explanation:

Answer:

85t

Step-by-step explanation:

1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

hope this helps

8 0
3 years ago
Read 2 more answers
Approximate the value of each of the irrational numbers below to the nearest thousandth.
Marta_Voda [28]

ANSWER

\sqrt{13}  = 3.606

to the nearest thousandth.

EXPLANATION

The given irrational number is

\sqrt{13}

We use the calculator to evaluate this to obtain,

\sqrt{13}  = 3.605551...

To round to the nearest thousandth means we are rounding to 3 decimal places.

The third decimal place is 5.

The next number is 5 so we round up.

\sqrt{13}  = 3.606

4 0
3 years ago
Which of the following equations is represented by the graph?
Greeley [361]

Answer:

••••••••••••••••••••The answer is Y=2/3x

6 0
3 years ago
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Please help me with this question I also need to see the steps if possible!
umka21 [38]

Hi there!

To solve, we must use the following trig identity:

sin(u - v) = sin(u)cos(v) - sin(v)cos(u)

We can rewrite the left hand side of the equation as:

\frac{sin(u)cos(v)-sin(v)cos(u)}{sin(u)cos(v)}

Split the fraction:

\frac{sin(u)cos(v)}{sin(u)cos(v)} - \frac{sin(v)cos(u)}{sin(u)cos(v)} =

First fraction reduces to 1:

1 - \frac{sin(v)cos(u)}{sin(u)cos(v)} =

Simpify each with common arguments:

1 - tan(v)cot(u)

4 0
3 years ago
Classify the following as monomial binomial trinomial and polynomial x^2 + y^2 +z^2
Fudgin [204]

Answer:

trinomial

Step-by-step explanation:

6 0
4 years ago
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