Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
Groups of four for the group of 288 and groups of five for the group of 360
Alright, so we plug (-2) in for x. (-2)^2 =4, and we can plug that in as 4(4)+(-2)+5. Next, 4*4=16, so we get 15+(-2)+5. After that, we get 15-2+5=18
Answer:
8n
Step-by-step explanation:
Answer:
1/6 p -4/5
Step-by-step explanation:
- 2/3p + 1/5 - 1 + 5/6p
When I combine like terms, I put them next to each other.
- 2/3p + 5/6p+ 1/5 - 1
We need to get a common denominator of 6 for the p terms
-2/3 *2/2 p + 5/6 p
-4/6p + 5/6 p
1/6 p
We need to get a common denominator of 5 for the contant terms
1/5 - 1*5/5
1/5-5/5
-4/5
Substituting these in
2/3p + 5/6p+ 1/5 - 1
1/6 p -4/5
