Answer:100
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
20
Discussion:
Let (x1,y1) = (-8, -6) and (x2,y2) = (4,10). Per the distance formula,
Distance = sqrt ( (x1-x2)^2 + (y1-y2)^2 ) so
Distance = sqrt ( (-8-4)^2 + (-6-10)^2 )
= sqrt( (12)^2 + (-16)^2 )
= sqrt( 144 + 256 )
= sqrt(400)
= 20
Thank you,
MrB
Answer:
I would say A
Step-by-step explanation:
The time that the ball is in the air is 2x the time that it takes to reach the maximum value.
In order to find the time at the max value you use the equation -b/2a where b is the value attached to the t and a is the value attached to t^2.
therefore, the time at the max value is -180/(2)(-16)=5.625 seconds
Total time= (5.625)(2)=11.25
