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rusak2 [61]
3 years ago
15

1. What would be the molarity of the sodium ion in solution.​

Chemistry
1 answer:
Yakvenalex [24]3 years ago
5 0
Therefore, the molar concentration of sodium ions is just 1 TIMES the molar concentration of sodium chloride. 1 times 0.110 equals 0.110. Therefore: [Na+] = 0.110. Na+ with square brackets around it is read as "molar concentration of Na+".
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AleksAgata [21]

Answer:

a) r = k × [A] × [B]²

b) 3

Explanation:

Let's consider the following generic reaction

A + B + C ⇒ Products

The generic rate law is:

r = k × [A]ᵃ × [B]ᵇ × [C]ⁿ

where

  • r: reaction rate
  • k: rate constant
  • a, b, n: reaction orders

This reaction is first order in A, second order in B, and zero order in C. The rate law is:

r = k × [A]¹ × [B]² × [C]⁰

r = k × [A] × [B]²

The overall order of the reaction is the sum of the individual reaction orders.

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3 years ago
How many moles of O2 are needed to react with 2.35 mol of C2H2?
Mrrafil [7]
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

x =  \frac{2.35 \times 5}{2}  = 5.875 \: mol
answer: 5.875 mol
5 0
3 years ago
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Dafna1 [17]

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A chemical reaction can theoretically produce 137.5 grams of product, but in actuality 112.9 grams are
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<h3>Answer:</h3>

82.11%

<h3>Explanation:</h3>

We are given;

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  • Actual mass of the product is 112.9 g

We are supposed to calculate the percentage yield

  • We need to know how percentage yield is calculated;
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Thus;

% yield = (Actual mass ÷ Experimental mass) × 100%

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Therefore, the percentage yield of the product is 82.11 %

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