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3 years ago

8

Please show the answer with the work, GodBless.

1 answer:

Yanka [14]3 years ago

8 0

Well, we know that y=1/2x+5 from the first equation. if we substitute that into the second equation, it becomes 2x + 1/2x +5 =1. solve for x. 2x+1/2x= -4, 2 1/2x=-4, x=-1.6. plug that in to one of the equations. 2(-1.6)+y=1, -3.2+y=1, y=-2.2. the solution is (-1.6, -2.2)

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chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

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Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

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Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

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So, $a^2-1=(a-1)(a+1)$

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Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

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