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Liula [17]
3 years ago
7

The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula

tion mean. If a random sample of 27 text messages is taken and results in a sample mean of 25 characters, find a 95% confidence interval for the population mean. Round your answers to two decimal places.
Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

45

Step-by-step explanation:

+hhsbsbbsjahsgsbsnkakwhsgevssv

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When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.
Juliette [100K]
x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0

Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution

x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \  0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \  0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \  0

Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}
6 0
3 years ago
There were 166 paid admissions to a game. The price was $2 for adults and $.75 for children. The amount of data taken in was $29
JulijaS [17]

Answer:the number of adults that attended the game is 135.

the number of children that attended the game is 31

Step-by-step explanation:

Let x represent the number of adults that attended the game.

Let y represent the number of children that attended the game.

There were 166 paid admissions to a game. This means that

x + y = 166

The price was $2 for adults and $.75 for children. The amount of data taken in was $293.25. This means that

2x + 0.75y = 293.25 - - - - - - - - - - 1

Substituting x = 166 - y into equation 1, it becomes

2(166 - y) + 0.75y = 293.25

332 - 2y + 0.75y = 293.25

- 2y + 0.75y = 293.25 - 332

- 1.25y = - 38.75

y = - 38.75/- 1.25

y = 31

x = 166 - y = x = 166 - 31

x = 135

5 0
3 years ago
HELP
kherson [118]

Answer: For the equation simply substitute 30 in for v and 4 in for s in the equation given, so H=-16t^2+30t+4

Part 2.

If the juggler misses the ball, you wish to know the time that it takes for the ball to travel the four feet from his hand to the ground, so respectively,

4=-16t^2+30t+4 or 0=-16t^2+30t or 0 = -16t+30,

solving for t, t =30/16 seconds or 1.875 seconds

Step-by-step explanation:

4 0
3 years ago
I don't know how to do this
Phantasy [73]
I completely agree with the above statement
3 0
3 years ago
0.3(3a-4)-0.05(8a)(-7a)
Anit [1.1K]

Answer:

2.8a²+0.9a - 1.2

Step-by-step explanation:

Given the expression 0.3(3a-4)-0.05(8a)(-7a)

Expand using the distributive law

0.3(3a-4)-0.05(8a)(-7a)

0.3(3a)-0.3(4)-0.05(8a)(-7a)

0.9a-1.2 - 0.05(8a)(-7a)

0.9a - 1.2 + 2.8a²

Rearrange

2.8a²+0.9a - 1.2

Hence the required expression is 2.8a²+0.9a - 1.2

3 0
2 years ago
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