Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
More
Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Should be 22.5
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Hope this helps you
Answer: The slope is: "3" ; which does not appear among the answer choices given.
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The slope, "m" is calculated as follows:
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Given two coordinates on a line;
m = (y₂ − y₁) / (x₂ − x₁) ;
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We are given the following 2 (TWO) coordinates:
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1) (5,2) ; which is: (x₁ ,y₁) ; so x₁ = 5 ; y₁ = 2 ; AND:
2) (7,8); which is: (x₂ ,y₂) ; so x₂ = 7; y₂ = 8 ;
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So; m = (y₂ − y₁) / (x₂ − x₁) = (8−2) /.(7−5) = 6/2 = 3 .
m = 3. The slope is: 3 ; which does not appear among the answer choices given.
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Alternately,
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We are given the following 2 (TWO) coordinates:
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1) (7,8) ; which is: (x₁ ,y₁) ; so x₁ = 7 ; y₁ = 8 ; AND:
2) (5,2); which is: (x₂ ,y₂) ; so x₂ = 5; y₂ = 2 ;
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So; m = (y₂ − y₁) / (x₂ − x₁) = (2−8) / (5−7) = -6/-2 = 3 .
m = 3. The slope is 3 ; which does not appear among the answer choices given.
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Answer:
Haeather ran at a speed of 5 miles per hour.
Step-by-step explanation:
Given that last week at the park Haeather ran 4 miles in 48 minutes, to determine what was Haeather rate of speed in miles per hour the following mathematical calculation must be performed:
48/4 = 12
Thus, Haeather ran 1 mile every 12 minutes.
60/12 = 5
1 x 5 = 5
Therefore, Haeather ran at a speed of 5 miles per hour.
