Each day, Steve walked 1/12 mile more than the previous day. The first day he walked 1/12, the second day he walked 2/12 mile, t
he third day he walked 3/12 mile. On which day did the sum of his walks total at least 1 complete mule?
1 answer:
1st day = 1/12
2nd day = 2/12
3rd day = 3/12
4th day = 4/12
5th day = 5/12
6th day would be = 6/12
If it continues in that order, the sum of the walks would total 1 mile when:
They all add up to 12/12
Add = 1/12 + 2/12 + 3/12 + 4/12 = 10/12
That is still not up to 12/12
So we add up the 5th day also = 10/12 + 5/12 = 15/12 = 1 3/12 miles
So on the 5th day the sum of his walks total at least 1 completed mile.
At least 1 means 1 and above. As you can see the answer we got 1 3/12 is already more than 1.
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