It's 96 pages that it would print in one hour
Answer:
theres no diagram
Step-by-step explanation:
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
The formula of a slope:

We have the points A(-6, 6) and B(12, 3). Substitute:

Therefore we have
.
Put the coordinates of the point B to the equation:

<em>add 2 to both sides</em>

Answer:

The graph intersects the x-axis twice. It intersects at the points of (-1,0) and (2.5,0). The graph is attached.