First, multiply the number of feet it takes for one balloon by the number of balloons filled daily.
0.5 * 80 = 40
So, 40 cubic feet is 20% of one tank. Now, unless you remember how to find what 40 is 20% of, simply play around with some numbers on your calculator until you find that 200 * 0.20 = 40. I would love to explain how to find that part with an actual formula, but I don't remember how. :/ Hope this helped.
Answer:
The base and height of the garden are 4.60 ft and 5.60 ft.
Step-by-step explanation:
The area of the garden is, <em>A</em> = 24 ft².
The base height of the garden are:
base (<em>b</em>) = 6x - 4
height (<em>h</em>) = x + 3
Compute the value of <em>x</em> as follows:
The last equation is a quadratic equation.
Compute the roots of the quadratic equation as follows:
The value of base and height are:
Thus, the base and height of the garden are 4.60 ft and 5.60 ft.
Answer:
idk what this is but plz mark brainliest!
Step-by-step explanation:
Answer:
the cyclists rode at 35 mph
Step-by-step explanation:
Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then
distance= speed*time
since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :
time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train
thus denoting v as the speed of the cyclists :
7/8*L / v = L / 40 mph
v = 7/8 * 40 mph = 35 mph
v= 35 mph
thus the cyclists rode at 35 mph
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
