<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
The total number of dancers in the school is 150.
Step-by-step explanation:
from what I can see there are 2 options to make the 2 triangles congruent :
either the opposite sides must be equal or the neighboring sides must be equal.
so, either
5x = 3x + 10
and
5x - 2 = 4x + 3
or
5x = 4x + 3
and
5x - 2 = 3x + 10
for the first
5x = 3x + 10
2x = 10
x = 5
control
5x - 2 = 4w + 3
5×5 - 2 = 4×5 + 3
23 = 23
correct.
for the second
5x = 4x + 3
x = 3
control
5×3 - 2 = 3×3 + 10
15 - 2 = 9 + 10
13 = 19
no, not a valid solution.
so, x = 5
Step-by-step is this the answer you wanted thanks for correcting me
