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saveliy_v [14]
3 years ago
10

Elena uses 12 red beads to make 4 bracelets how many red beads will Elena need to make 12 bracelets ,

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Part 1:

Answer:36 red beads

Step-by-step explanation:

12/4=3 beads per bracelet

3x12=36 red beads

Part 2:

Answer:48 red beads

Explanation:

We know 3 red beads per bracelet.

3x16=48 red beads

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2. State whether the change is increasing or decreasing. Round your percent of change to the nearest integer percent. originally
marysya [2.9K]

Answer:

The change is increasing with a percentage of change of 64%

Step-by-step explanation:

Since we have the present grater than the original, then the change is increasing

Secondly, we want to calculate the percent of change

Mathematically , that will be ;

(present - original)/original * 100%

= (90-55)/55 * 100%

= 35/55 * 100% = 63.63 which is approximately 64%

7 0
3 years ago
Explain why the graph shown may be misleading. (please help)
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Be cause for every one car truck or midsize there is 10 vehicles
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3 years ago
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Letf(x)=(x+2)2.
Troyanec [42]

Answer: it is stretched vertically by a factor of 3

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I hope This help;)

7 0
3 years ago
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What is the solution set for -4 x - 10 ≤ 2?<br> A. x ≤ -3<br> B. x ≥ -3<br> C.x ≤ -3<br> D. x ≥ 2
kramer

Answer:

B. x ≥ -3

Step-by-step explanation:

-4 x - 10 ≤ 2

add ten by both sides

-4x≤12

divide -4 by both sides

x ≤ -3

BUT because you divded  you have to switch the sign so

x ≥ -3

6 0
3 years ago
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Sistema de ecuaciones.5x+2y=-152x-2y=-6
Zolol [24]

Tnemos el sisema de ecuaciones:

\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

\begin{gathered} 2x-2y=-6 \\ 2\cdot(-3)-2y=-6 \\ -6-2y=-6 \\ -2y=-6+6 \\ -2y=0 \\ y=0 \end{gathered}

Respuesta: x=-3, y=0

7 0
1 year ago
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