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Lelu [443]
3 years ago
6

2. A ball is dropped from rest. The acceleration due to gravity is 10m/s? and the time it

Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

STEP BY STEP

V = S/T

V= 10/5

V = 2 m/s

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2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

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The momentum after collision will be given by (9+27)*0.9=32.4

Relating the two then 9v+13.5=32.4

9v=18.5

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Rounded off, v is approximately 2.06 m/s

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