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max2010maxim [7]
3 years ago
6

The one to one functions G and H are defined as follow

Mathematics
1 answer:
dem82 [27]3 years ago
7 0
G=\{(-8,1),(1,5),(4,-5),(8,-9)\}\\\\\Rightarrow\ \ \ G^{-1}=\{(1,-8),(5,1),(-5,4),(-9,8)\}\ \ \ \Rightarrow\ \ \ g^{-1}(1)=-8\\\\H(x)=3x+4\ \ \ and\ \ \ D_H=R\\\\ 3x=H(x)-4\ \ \ \Rightarrow\ \ \ x= \frac{H(x)-4}{3}\\\\h^{-1}(x)= \frac{x-4}{3} \ \ \ and\ \ \ D_{h^{-1}}=R\\\\\\(h^{-1}\circ h)(-2)=-2\\\\h^{-1}\bigg {(}h(-2)\bigg{)}=h^{-1}\bigg {(}3(-2)+4\bigg{)}=h^{-1}(-2)= \frac{-2-4}{3} = \frac{-6}{3} =-2
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<h2>Answer:</h2>

<u>x= 90°</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

4 + 2 sin(x)= 14-8 sin(x)

<h3>2. Subtract "4" from both sides of the equation.</h3>

-4+4 + 2 sin(x)= 14-8 sin(x)-4\\ \\2 sin(x)= 10-8 sin(x)

<h3>3. Add "8sin(x)" to both sides of the equation.</h3>

2 sin(x)+8 sin(x)= 10-8 sin(x)+8 sin(x)\\ \\10 sin(x)= 10

<h3>4. Divide both sides by 10.</h3>

\frac{10 sin(x)}{10} = \frac{10}{10} \\ \\sin(x)=1

<h3>5. Apply the arcsin of sin^-1 to both sides of the equation.</h3>

arcsin(sin(x))=arcsin(1)\\ \\x=90

<h3>6. Conclude.</h3>

<u>x= 90°</u>.

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Step-by-step explanation:

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