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3 years ago

8

Tiffany is sending a package that may not exceed 6 pounds. The package contains books that weigh a total of 9 3/8 pounds. The ot

her items to be sent away are 3/5 the weight of the books. Will Tiffany be able to send the package.

1 answer:

lorasvet [3.4K]3 years ago

5 0

It will be too heavy unless she divides the items into two separate packages

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What is 1,711,239 rounded to the nearest hundred?

Elina [12.6K]

The hundreds place is filled by a 2.

The number next to it is a 3, which tells how to round. A 3 says 'stay' with the 2. The remaining places after it become zeros.

1,711,200

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2 years ago

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Find an equation of the line passing through the pair of points (2,3) and (5,9). Write the equation in the form Ax + By = C.

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Answer:

- 2x + y = - 1 , so the B is correct.

Step-by-step explanation:

+ Because of "the line passing through the pair of points (2,3) and (5,9)", that means the line has the equation y = ax + b where a = (9-3)/(5-2)= 6/3= 2

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+ The equation of this line is y = 2x - 1 or in the form:

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3 years ago

Is 0.444444444444444... a rational number? explain

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3 years ago

Determine the greatest common factor of 15xy^7z and 30x^2y^7z

yawa3891 [41]

Answer:

$15x {y}^{7} z$

Step-by-step explanation:

<h3>Factorize the Expressions</h3>

$15x {y}^{2} z = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

$30 {x}^{2} {y}^{7} z = 2 \times 3 \times 5 \times x \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Factor out the Common Factors</h3>

$gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Multiply the Common Factors</h3>

$3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z = 15x {y}^{7} z$

The Factored expressions are

$15x {y}^{7} z$

And

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3 years ago