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kodGreya [7K]
3 years ago
10

HELPPPPP HELPPPPP HELPPPP!!!!! AHHHHHHHHHHHHHHJJJJSJDJDJ

Mathematics
1 answer:
erica [24]3 years ago
8 0

Answer:

QRS equals to 91

Step-by-step explanation:

50 + 41 = 91

You might be interested in
F(x) = x2 + 1 g(x) = 5 – x (f + g)(x) =
noname [10]
(f + g)(x) = x^2 + 1 + <span>5 – x = x^2 - x + 6

hope that helps</span>
6 0
3 years ago
Solve the system of equations.
Sliva [168]

Answer:

(5,0)

Step-by-step explanation:

x = 5

y = 0

(I love these kind of q's, if anyone needs help!)

:D

4 0
3 years ago
A random sample of 30 males with online dating profiles are recruited for a study about lying in online dating profiles. Each ma
laiz [17]

Answer:

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 30 - 1 = 29

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0452

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0452\frac{0.81}{\sqrt{30}} = 0.3

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.57 - 0.3 = 0.27 inches.

The upper end of the interval is the sample mean added to M. So it is 0.57 + 0.3 = 0.87 inches.

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

3 0
2 years ago
Someone help me pls :))
elena-14-01-66 [18.8K]

Answer:

x = 16

Step-by-step explanation:

5 0
3 years ago
Help me please!!!!!!!!
EleoNora [17]

Answer:

The sum is approximately 42.56

Step-by-step explanation:

Notice that you are dealing with a series whose first term is :

3 \, (\frac{3}{2})^0 = 3\,*\,1=3

followed by  sum of terms of the form:

a_1=3\,(\frac{3}{2} )^1\\a_2=3\,(\frac{3}{2} )^2\\a_3=3\,(\frac{3}{2} )^3\\a_4=3\,(\frac{3}{2} )^4\\a_5=3\,(\frac{3}{2} )^5

and this is a geometric sequence of common ratio given by:  \frac{3}{2}   (the value you need to multiply one term of the geometric sequence in order to find the following one)

Then, we can use the general formula for a partial sum of a geometric sequence for these last 5 terms for which m=5, the common ratio r =  \frac{3}{2} , and a = 3:

S_m=a(r^m-1)/(r-1)\\S_5=3 ((\frac{3}{2})^5 -1)/(\frac{3}{2}-1)\\S_5=39.5625

So, the total sum of the six terms is:

Total sum = 3 +39.5625 = 42.5625

which can be rounded to hundredth: 42.56

4 0
3 years ago
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