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Flauer [41]
2 years ago
14

I need help please provide with the correct answer. it is due at 11:59 pm

Mathematics
1 answer:
expeople1 [14]2 years ago
6 0
I think the answer is d
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Solve the system y= -x + 7 and y=0.5(x - 3)^2
solniwko [45]

Answer:

(- 1, 8 ) and (5, 2 )

Step-by-step explanation:

Given the 2 equations

y = - x + 7 → (1)

y = 0.5(x - 3)² → (2)

Substitute y = 0.5(x - 3)² into (1)

0.5(x - 3 )² = - x + 7 ← expand and simplify left side

0.5(x² - 6x + 9) = - x + 7 ( multiply both sides by 2 )

x² - 6x + 9 = - 2x + 14 ( subtract - 2x + 14 from both sides )

x² - 4x - 5 = 0 ← in standard form

(x - 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

Substitute these values into (1) for corresponding values of y

x = 5 : y = - 5 + 7 = 2 ⇒ (5, 2 )

x = - 1 : y = 1 + 7 = 8 ⇒ (- 1, 8 )

8 0
3 years ago
Read 2 more answers
X+y=3<br> 2x-y=0 <br> substituition method
Veronika [31]

Answer:

(1, 2 )

Step-by-step explanation:

x + y = 3 (subtract x from both sides )

y = 3 - x → (1)

2x - y = 0 → (2)

Substitute y = 3 - x into (2)

2x - (3 - x) = 0

2x - 3 + x = 0

3x - 3 = 0 ( add 3 to both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Substitute x = 1 into (1)

y = 3 - 1 = 2

solution is (1, 2 )

5 0
2 years ago
Could someone help me please 2x+5y=35
TEA [102]

• look below those are the options for y or x bc you didnt say which one we solving for.

3 0
3 years ago
Which system of equations can be graphed to find the solution(s) to 4x2 = x2 – 7?
Usimov [2.4K]

4x^2 = x^2 - 7

In order to find the solution by graphing we need to make two equation with x and y terms

we use Left hand side 4x^2 for first equation and right side x^2 -7 for second equation.

So the equation becomes

first equation y=4x^2

Second equation y= x^2 - 7

y= x^2 \ and \ y= x^2-7 are the system of equations that can be graphed to find solution

5 0
3 years ago
Read 2 more answers
Does anyone know how to solve this?
Law Incorporation [45]

Answer:

{ \boxed{ \tt{f(x) = 5 \cos3x \degree}}} \\  {  \green{f(x) = f(60) : x = 60}}\\ f(60) = 5 \cos(3 \times 60) \degree \\ f(60) = 5 \cos(180 \degree)  \\ but \:  \cos(180 \degree)  =  - 1\\  { \boxed{ \bf{answer : f(60) =  - 5}}} \\  \\ { \underline{ \blue{becker \: jnr}}}

5 0
3 years ago
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