The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2. Obi spent ?20 that day. Obi now had ?8 less than Rudy. How
much did they have initially altogether?
2 answers:
Answer:
Altogether, they had ?28
Step-by-step explanation:
Had Obi spent only ?12, they would have been even. Thus ?12 is the same as 5-2 = 3 "ratio units". So, each "ratio unit" is worth ?12/3 = ?4.
Then Obi started the day with 5·4 = 20, and Obi started the day with 2·4 = 8. Obi ended with 0, which is 8 less than Rudy.
Altogether, they started with 20 + 8 = 28 of whatever a ? is.
Answer:
Money they have initially altogether = 28
Step-by-step explanation:
The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2.
Money Obi has = 5 r
Money Rudy has = 2 r
Obi spent 20 that day and bi now had 8 less than Rudy
5r -20 = 2r - 8
3r = 12
r = 4
Initial money they have
Obi = 5r = 5 x 4 = 20
Rudy = 2 x 4 = 8
Altogether they have 20+8 = 28
Money they have initially altogether = 28
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From the table there is 24 houses with 2 bathrooms and 3 bedrooms
there is a total of 30 houses with 2 bathrooms
the probability is 24 /30 = 0.8
Answer:
Option C is correct
Step-by-step explanation:
5c – 20 ≤ 15c + 10
<=> 5c - 15c ≤ 20 + 10
<=>-10c ≤ 30
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Hope this helps!
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