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Viefleur [7K]
3 years ago
5

7. -3.5, 5, 0.6,-0.2 Witch one is least to greatest

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

-3.5,-0.2,0.6,5 ... is the answer

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In each triangle p is the circumcenter use circumcenter theorem to solve for the givin values
timurjin [86]

Answer:

Circumcenter theorem states that the vertices of the each triangle are equidistant from the circumcenter.

As per the statement:

It is given that: P is the circumference

From the given figure:

CP = 12 units.

then;

by circumcenter theorem;

AP= BP =CP = 12 units.

Next find the value of AB:

Labelled the diagram:

AD = 11 units

then;

AB = AD+DB

Since: AD=DB [You can see it from the given figure]

then;

AB = 2AD = 2(11) = 22 units

Therefore, the value of BP and AB are: 12 units and 22 units

4 0
3 years ago
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Can anyone show me the steps to factor 3x^2+7x+2?
Helga [31]
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3x^2+7x+2
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5 0
3 years ago
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chris has 3 1/2 boxes of tomatoes at his restaurant he uses 1 3/4 boxes to make tomato sauce for tonight's dinner. How many boxe
Sladkaya [172]

Answer:

1 3/4

Step-by-step explanation:

3 1/2 boxes of tomatoes currently. uses 1 3/4, taking it away basically.

3 1/2 - 1 3/4

3 2/4 - 1 3/4 ;; i did this with finding a common denominator for it to be easier for me to solve.

3 - 1 = 2

2/4 - 3/4 = -1/4

2 + -1/4 = 1 3/4

correct me if wrong.

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3 years ago
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The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation
Olegator [25]
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or       4k - 1 = 13.  Then 4k = 14, and k = 14/4, or (after reduction)  k = 7/2   

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.
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32.309 on expanded form
Alisiya [41]
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