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BaLLatris [955]
3 years ago
13

Which are the roots of the equation 3m^2-5m+1=0

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

Step-by-step explanation:

This is a quadratic equation, with coefficients 3, -5 and 1.

The discriminant, b² - 4ac, turns out to be (-5)² - 4(3)(1), or 25 - 12  =  13

Thus, the roots are:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

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2 years ago
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kakasveta [241]

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3 years ago
Find the vertical asymptote for y=x^2-5x/x^2-x-2
grigory [225]

Answer:

vertical asymptote at x=2  and x=-1

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now factor left hand side

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7 0
3 years ago
If the standard deviation of a data set was originally 5, and if each value in the data set was multiplied by 3.6, what would be
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You would take 5 and multiply it by 3.6 which gives you 18. I believe that is how you would do that problem. Hope it helped.
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Read 2 more answers
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