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BaLLatris [955]
3 years ago
13

Which are the roots of the equation 3m^2-5m+1=0

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

Step-by-step explanation:

This is a quadratic equation, with coefficients 3, -5 and 1.

The discriminant, b² - 4ac, turns out to be (-5)² - 4(3)(1), or 25 - 12  =  13

Thus, the roots are:

       -(-5) ± √13             5 ± √13

x = ----------------------- = ---------------

              2(3)                       6

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Answer:

x = -5.25 or 21/4

Step-by-step explanation:

When break the bracket out, if there is a minus sign in front of the bracket, when we break it out, the sign inside the bracket would become positive:

67 = 18 - (8x - 7)

67 = 18 - 8x - (-7)

67 = 18 - 8x + 7

67 = 18 + 7 - 8x

67 = 25 - 8x or rewrite for easier look: 25 - 8x = 67

25 - 8x = 67

8x = 25 - 67

8x = -42

Divide both side by 8, we got:

x = -42 / 8

x = -5.25 or 21/4

Hope this helped :3

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Answer:

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