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Zarrin [17]
3 years ago
8

arnita swims in a pool that is 50 meters long. everyday arnita swims 10 lengths of the the pool. After 5 days, how many kilomete

rs has arnita swum?
Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

After 5 days Arnita has swum 2.5 kilometers.

Step-by-step explanation:

50 x 10 = 500 lengths of the pool per day

500 x 5 = 2,500 meters

2,500 meters = 2.5 kilometers

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What is the next term if the geometric sequence 192,48,12
VladimirAG [237]

the numbers are being divided by 4 so 12/4 =3

 next number is 3

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3 years ago
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Find the missing angle in the triangle,<br> x°<br> 36°<br> 111°
andriy [413]

Answer:

33°

Step-by-step explanation:

you add the two numbers together and subtract from 180° to get your answer

7 0
3 years ago
Assume that there is a 4​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
kap26 [50]

Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
3 years ago
What is the volume of the composite figure? (Round to the nearest hundredth. Use 3.14 for x.)
marshall27 [118]

The volume of the composite figure is the third option 385.17 cubic centimeters.

Step-by-step explanation:

Step 1:

The composite figure consists of a cone and a half-sphere on top.

We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying \frac{1}{3} with π, the square of the radius (r²) and height (h). Here we substitute π as 3.1415.

The radius is 4 cm and the height is 15 cm.

The volume of the cone :

V = \frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.1415)(4^{2} )(15) = 251.32 cubic cm.

Step 3:

The area of a half-sphere is half of a full sphere.

The volume of a sphere is given by multiplying \frac{4}{3} with π and the cube of the radius (r³).

Here the radius is 4 cm. We take π as 3.1415.

The volume of a full sphere \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.1415) (4^{3}) = 268.07 cubic cm.

The volume of the half-sphere =\frac{1}{2} (268.07) = 134.037 cubic cm.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume 251.32+134.037 = 385.357 cub cm. This is closest to the third option 385.17 cubic centimeters.

5 0
4 years ago
Jskawlowlekdkckfkdkdkdkkfkfkfkfkfkr
ICE Princess25 [194]
Use photo math it works very well!
7 0
3 years ago
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