Answer: I want to say 30 degrees you have to put the degree simble
Step-by-step explanation:
a regular polygon has all equal sides.
a PENTA=5, pentagon has 5 sides, so a regular pentagon has 5 equal sides.
![\bf \textit{area of a polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=K\\ p=\stackrel{3+3+3+3+3}{15} \end{cases}\implies A=\cfrac{1}{2}K15\implies A=\cfrac{15}{2}K](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Barea%20of%20a%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3DK%5C%5C%20p%3D%5Cstackrel%7B3%2B3%2B3%2B3%2B3%7D%7B15%7D%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7DK15%5Cimplies%20A%3D%5Ccfrac%7B15%7D%7B2%7DK%20)
Answer:
by 
by 
Step-by-step explanation:
In this problem I'm assuming the office is rectangular.
so
The area of rectangle is equal to

where
L is the length of the rectangle
W is the width of the rectangle
In this problem we have

so
------> equation A
Find two possible dimensions of the office
case A) Assume a length side L and find the value of W in the equation A
so
For 
substitute in the equation and solve for W


The dimensions are
by 
case B) Assume a length side L and find the value of W in the equation A
so
For 
substitute in the equation and solve for W


The dimensions are
by 