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3 years ago

Hello, can anyone help please? :D

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

Answer:

just guess

Step-by-step explanation:

i got it right

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Lucy spent $15 of her money. If m represents her money, which expression shows how much money Lucy will have left?

mote1985 [20]

It’s B. Your answer is B, because she is taking 15 away from her money she said already

6 0

2 years ago

Read 2 more answers

5x-2y=-6 3x-4y = -26

snow_tiger [21]

For this case we must solve the following system of equations:

$5x-2y = -6\\3x-4y = -26$

We multiply the first equation by -2:

$-10x + 4y = 12$

We add the new equation with the second one:

$-10x + 3x + 4y-4y = 12-26$

We have different signs subtracted and the sign of the major is placed:

$-7x = -14\\x = \frac {-14} {- 7}\\x = 2$

Now we find the value of the variable "y":

$3x-4y = -26\\3 (2) -4y = -26\\6-4y = -26\\-4y = -26-6\\-4y = -32\\y = \frac {-32} {- 4}\\y = 8$

Thus, the solution of the system is given by:

$(x, y) :( 2,8)$

Answer:

$(x, y) :( 2,8)$

3 0

3 years ago

Diego is making a trail mix for him and his friends to take with them on a hike next week he mixes 4 2/6 pounds of nuts, 3 3/6 p

Sav [38]

Answer:

31 bags

Step-by-step explanation:

Lets see the total number of pounds he mixed with nuts, peanuts, and chocolate chips.

There is a total of 10 and 1/3 pounds in total. To see how many 1/3rd bag he can have, we have to divide the total by 1/3. So we have:

So, there can be 31 bags

5 0

3 years ago

How do I find the perimeter of similar triangles? (Geometry)

Igoryamba

I hope this helps you

3y-2=y+4

2y=6

y=3

Perimeter=4+6+7

Perimeter=17

6 0

3 years ago

Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago