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valkas [14]
3 years ago
12

If x=6 and y= -2, what is the value of 3xy+ 2x²- y³

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

44

Step-by-step explanation:

<u>Step 1:  Set x to 6 and y to -2 </u>

<u />3xy + 2x^2 - y^3

3(6)(-2) + 2(6)^2 - (-2)^3

-36 + 72 - (-8)

36 + 8

44

Answer:  44

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Do you mean g as in the acceleration due to gravity on Earth?

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Step-by-step explanation:

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Atiker wants to uile a rectangular wall which reasures Ambuy 2.5 m,
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Answer:

Step-by-step explanation:

There are 100 cm in 1 meter. the dimensions are 400cm by 250cm. depending on which way you turn them, they will fit better. if you take 400 divided by 16, you will have a row of 25 wide and if you divide 250 by 10, you will have a length of 25. you now have 25 rows of 25. 25x25 is 625 tiles.

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2 years ago
21 Maria sold small boxes of candy for $1 and
Anna35 [415]

Answer:

There where 10 <u>more</u> Small boxes sold than Large boxes.

Step-by-step explanation:

<u>This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable. </u>

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable y and an Independent variable x. In a system of Two Linear equations we have<u> two equations</u> of the same variable sets (thus Two Independent variables) so in this case both y and x will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

<u>Given Information:</u>

  • Small Boxes (lets call them s) cost $1 per box
  • Large Boxes (lets call them l) cost $4 per box
  • Total Number of Boxes sold is 30
  • Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

s+l=30        Eqn(1): Total Number of Boxes

1s+4l=60     Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, s and l respectively.

From Eqn(1) we see that

s=30-l      Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for l as:

1(30-l)+4l=60

30-l+4l=60       Factored out bracket

3l=60-30          Gather similar terms on each side and simplify

3l=30

l=\frac{30}{3}

l=10

Plugging in the value for l=10 in Eqn(3) we have

s=30-10\\s=20

So we know that they were<u> 10 Large Boxes and 20 Small Boxes sold</u>, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

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Never
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