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xenn [34]
3 years ago
10

6. Reduce the fractions, if possible. (x + 2)(x +1/3) ​

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

(3x+1) (x+2)

---------------

        3

Step-by-step explanation:

(x+2) (x+1/3)

Stack and add them

(x+2)

(x+1/3)

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Given vectors u = ⟨–3, 2⟩ and v = ⟨2, 1⟩, what is the measure of the angle between the vectors?
hjlf

The measure of the angle between the vectors

$\arccos[ (-\sqrt{13 } i )/ (\sqrt{5 }) ]\\\sqrt{5 }.

What is the measure of the angle between the vectors?

Given:

$\mathrm{u}=\langle -3,2\rangle$ and $v=\langle 2,1\rangle$

Computing the angle between the vectors, we get

$\quad \cos (\theta)=\frac{\vec{a} \cdot \vec{b}}{|\vec{a}| \cdot|\vec{b}|}$

To estimate the lengths of the vectors, we get

Computing the Euclidean Length of a vector,

$\left|\left(x_{1}, \ldots, x_{n}\right)\right|=\sqrt{\sum_{i=1}^{n}\left|x_{i}\right|^{2}}$

Let, $\mathrm{u} &=\langle -3,2\rangle \\ and $\mathrm{v} &=\langle 2,1\rangle \\

If $\mathrm{u} &=\langle -3,2\rangle \\

$|u| &=\sqrt{-3^{2}+(2)^{2}} \\

$&=\sqrt{5}i \\ and

$\mathrm{v} &=\langle 2,1\rangle \\

$|v| &=\sqrt{2^{2}+(1)^{2}} \\

$&=\sqrt{5}

Finally, the angle is given by:

Computing the angle between the vectors, we get

$ $\cos (\theta)=\frac{\vec{a} \cdot \vec{b}}{|\vec{a}| \cdot|\vec{b}|}$

$&\cos (\Phi)=-\sqrt{13 } i/ \sqrt{5 } \\

simplifying the above equation, we get

$&\Phi=\arccos (\cos (\Phi))

$=\arccos[ (-\sqrt{13 } i )/ (\sqrt{5 }) ]\\\sqrt{5 }

Therefore, the measure of the angle between the vectors

$\arccos[ (-\sqrt{13 } i )/ (\sqrt{5 }) ]\\\sqrt{5 }.

To learn more about vectors refer to:

brainly.com/question/19708440

#SPJ4

8 0
2 years ago
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