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jok3333 [9.3K]
3 years ago
7

Т -2 > - 7 6 what’s the solution??

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

t/7=6 We simplify the equation to the form, which is simple to understand t/7=6 Simplifying: + 0.142857142857t=6

Step-by-step explanation:

hope this helps !!

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In a swimming class, 2/5 of the participants are girls. there are 24 boys in the class. find the total number of participants in
jeyben [28]
30 because 2/5 are girls so 3/5 are boys and 24/3 +8 so    1/5=8   so   8*5 +  40 kids 

Hope this helped

please give me a thank you

8 0
3 years ago
Find the Area and Perimeter!
olga_2 [115]

Area of a triangle is 1/2 x base x height.

base = 12

Height = x+6

Area = 1/2 * 12 * x+6

Area = 1/2 * 12x * 72

Area = 6x + 36



Perimeter is the sum of the 3 sides:

x-7 + 12 + 2x+5

3x -2 + 12

3x+10


The last choice is the correct answer.



7 0
3 years ago
What is the value? <br><br> -8 * 2/3
Slav-nsk [51]

Answer: -5 2/3

Step-by-step explanation:

6 0
2 years ago
Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10
Brums [2.3K]

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

==>Interquartile range = Q3 - Q1 = 5-3 = 2

3 0
3 years ago
Solve the equation: 14&lt;2x−1≤20
mafiozo [28]

Answer:

7.5 < x≤10.5

Step-by-step explanation:

14<2x−1≤20

Add 1 to all sides

14+1<2x−1+1≤20+1

15<2x≤21

Divide each side by 2

15/2 <2x/2 ≤21/2

7.5 < x≤10.5

5 0
3 years ago
Read 2 more answers
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