Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
<span>-7 x (-9) = +63
because if we multiply negative by negative we obtain +</span>
Answer:
Step-by-step explanation:
- Total distance = 10 miles
- Total time = 2 hours
- Distance walked = x
- Speed walked = 2 mph
- Distance cycled = 10 - x
- Speed cycled = 15 mph
<u>Using the given data we can have the equation below to the time:</u>
- x/2 + (10 - x)/15 = 2
- 30x/2 + 30(10 - x)/15 = 30(2)
- 15x + 20 - 2x = 60
- 13x = 60 - 20
- 13x = 40
- x = 40/13
- x = 3.08 miles <em>rounded to 2 decimal places</em>
Answer:
A) Rectangle
Step-by-step explanation:
Hope this helps :D
