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tamaranim1 [39]
3 years ago
12

For art class, Samantha had to decorate two frames. On the larger frame, she used 7 feet of crepe paper. The smaller frame only

used 27 inches of crepe paper.
How many inches did she use altogether for the two frames?
A. 34 inches
B. 109 inches
C. 111 inches
D. 189 inches
Mathematics
1 answer:
aivan3 [116]3 years ago
5 0

Answer:

鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味鱼腥味 鱼腥味                鱼腥味

Step-by-step explanation:

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Analyze the diagram below and complete the instructions that follow.
Fynjy0 [20]

Answer:

it is d

Step-by-step explanation:

i jusdt took the test

5 0
3 years ago
For f (x) - 4x +1 and g(x) = ? -5, find (fºg)(4).
Alona [7]

(f\circ g)(x)=f(g(x))=4(x^2-5)+1=4x^2-19

(f\circ g)(4)=4\cdot4^2-19=64-19=\boxed{45}

Hope this helps.

5 0
3 years ago
Georgia built a model of the Empire State Building that is proportional to the actual building. The actual building is 187 feet
Illusion [34]

\frac{x}{10ft}  =  \frac{187ft}{1454ft}  \\ (10 \times 187) \div 1454 =  \\ 1.2861072902 \\ or \\ 1.3ft \: wide
8 0
3 years ago
(60 POINTS) PLEASE HELP ME!!!
Elan Coil [88]

Answer:

the second option

Step-by-step explanation:

The second option because there is no pattern.

8 0
4 years ago
Read 2 more answers
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
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