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kicyunya [14]
3 years ago
11

How do the different processes of a rock cycle change a rock? Which processes will form an igneous, sedimentary, and metamorphic

rock
Chemistry
1 answer:
Ksivusya [100]3 years ago
5 0
Answer: More than 700 different types of igneous rocks are known. Sedimentary rocks form by the compaction and cementing together of sediments, broken pieces of rock-like gravel, sand, silt, or clay. ... Metamorphic rocks form when the minerals in an existing rock are changed by heat or pressure below the surface.

Hope this helps (:
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In a reaction vessel, 17.6 g of solid chromium(III) oxide, Cr2O3, was allowed to react with excess carbon tetrachloride in the f
notsponge [240]

Answer:

72.53% is the yield of CrCl3

Explanation:

Given

Reaction:

Cr2O3(s) + 3 CCl4(l) → 2 CrCl3(s) + 3 COCl2(aq)

CCl4 is in excess and 17.6g  Cr2O3 present

The reaction yields 26.6g of CrCl3

To Find:

% yields of the reaction

Also given

Molar mass of CrCl3 = 158.35g/mol

Molar mass of Cr2O3 = 152.00 g/mol

By the stoichiometry of the reaction

1 mole of Cr2O3 gives  2 moles of CrCl3

0r

1 x1 52 g of Cr2O3 gives 2x 158.35 g of CrCl3

= 1 52 g of Cr2O3 gives 316.70 g of CrCl3

    17.6 g of Cr2O3 gives  (17.6÷152) × 316.70 g CrCl3

= 36.67 g CrCl3

but actual yield is only 26.6g

so % yield is (26.6 ÷÷ 36.67) × 100

= 72.53% is the yield of CrCl3

8 0
4 years ago
The region outside the nucleus where an electron can be found
Alex Ar [27]
The region where an electron is most likely to be is called an orbital
6 0
3 years ago
Complete each statement to identify the form of asexual reproduction.
Mrrafil [7]

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During  budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.

The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.

8 0
3 years ago
Read 2 more answers
A 4.3 L gas bubble at STP is heated to 984 K, and the pressure increases to 1520 mmHg. What is the new volume?
Natalka [10]

Answer:

v2=40.35L

Explanation:

p1v1/t1=p2v2/t2

v2=t2p1v1/t1p2

v2=984*760*22.4/273.15*1520

v2=40.35 L

5 0
3 years ago
What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?
Vladimir [108]

Answer:

<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>

Explanation:

The expression for Bohr velocity is:

v=\frac{Ze^2}{2 \epsilon_0\times n\times h}

Applying values for hydrogen atom,  

Z = 1

Mass of the electron (m_e) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

\epsilon_0 = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

v=\frac {2.185\times 10^6}{n}\ m/s

Given, n = 2

So,

v=\frac {2.185\times 10^6}{2}\ m/s

v=1.0925\times 10^6\ m/s

Kinetic energy is:

K.E.=\frac {1}{2}\times mv^2

So,

K.E.=\frac {1}{2}\times 9.1093\times 10^{-31}\times ({1.0925\times 10^6})^2

<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>

3 0
3 years ago
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