The gradient of the function is constant s the independent variable (x) varies The graph passes through the origin. That is to say when x = 0, y = 0. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear. I believe the answer is C. Hope I helped!
Answer:
Number one! :D
Step-by-step explanation:
3
−
1
=
3
−
1
3
−
1
+
1
=
3
−
1
+
1
0
=
0
Answer:
d. 0.538
Step-by-step explanation:
Given information.
Standard deviation is 4.3
Random sample of 10
Consider the following calculations
P (sample mean is within 1 month of population mean)=
P(-1*sqrt(10)/4.3 <Z<sqrt(10)/4.3)=P(-.735<Z<0.735)
=0.538
Answer:
The function would be linear because the rate of change is constant.
Step-by-step explanation:
Given
per minute
See attachment for complete question and options
First, we write the function that calculates the cost (C(t)) for t minutes.
This is calculated as:
Rewrite as:
A function that has the above format is referred to as a linear function which has the general format
Where
m represents the slope/rate and it is constant
From the list of given options, (a) is correct.
