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Natali5045456 [20]
3 years ago
9

Distance=100 meters Time=33.2 seconds Speed= pls help

Chemistry
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

3.01

Explanation:

Speed=distance/time

=100mtrs/33.2sec

=3.01m/s

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Sauron [17]
No because  most of them are forces
3 0
3 years ago
Complete and balance the following equation:
sertanlavr [38]
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 -> Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2

Br:
Multiply the reactant (left) side by 2 to balance.

O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.

N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.

You end up with the complete and balanced equation:

2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
4 0
4 years ago
60 POINTS + BRAINLIEST !! PLEASE HELP!!
uranmaximum [27]
To get moles. divide mass by molar mass.Molar mass of
Na is 23
and for Cl is 35.5.
the total molar mass of NaCl is 23+35.5 = 58.5mol/gUse the mass and divide by this number30.22g divide by 58.5mol/g and you will get 0.5166 mole.
Since the molecule has 1 Na to 1 Cl, and that the number of moles for NaCL is 0.5166. All of them would be 0.5166molesNa = 0.5166 x 1 = 0.5166molesCl = 0.5166 x 1 = 0.5166moles
to get number of atoms. Multiply your mole by Avogadro number which is 6.022x10^23Na = 0.5166 x 6.022E23 = 3.111x10^23Cl =  0.5166 x 6.022E23 = 3.111x10^23
5 0
4 years ago
How many grams of sodium make up 4.01×10^25 atoms
alexgriva [62]

Answer:

  • 5.74 ×10 25

Explanation:

3 0
3 years ago
For the following pair, indicate which element has the lower first ionization energy: Match the words in the left column to the
emmainna [20.7K]

<u>Answer:</u>

<u>For 1:</u> The correct answer is Ge.

<u>For 2:</u> The correct answer is Te.

<u>For 3:</u> The correct answer is Ba.

<u>For 4:</u> The correct answer is Ag.

<u>Explanation:</u>

Ionization energy is defined as the energy required to remove an electron from the outermost shell of an isolated gaseous atom. It is represented as E_i

X(g)\rightarrow X^+(g)+1e^-;E_i

Ionization energy increases as we move from left to right in a period. This happens because the atomic radius of an element decreases moving across a period, which increases the effective attraction between the negatively charged electrons and positively-charged nucleus. Hence, the removal of electron from the outermost shell becomes difficult and requires more energy.

Ionization energy decreases on moving from top to bottom in a group. This happens because the number of shells increases as we move down the group. The electrons get added in the new shell. So, the shielding of outermost electrons from the inner ones is more which decreases the attraction between the electrons and the nucleus. Hence, the removal of electron from the outermost shell becomes easy and requires less energy.

For the given options:

  • <u>Option 1:</u>

Chlorine is the 17th element of the periodic table belonging to Period 3 and Group 17.

Germanium is the 32nd element of the periodic table belonging to Period 4 and Group 14.

Hence, germanium will have smaller first ionization energy.

  • <u>Option 2:</u>

Tellurium is the 52nd element of the periodic table belonging to Period 5 and Group 16.

Selenium is the 34th element of the periodic table belonging to Period 4 and Group 16.

Hence, tellurium will have smaller first ionization energy.

  • <u>Option 3:</u>

Barium is the 56th element of the periodic table belonging to Period 6 and Group 2.

Titanium is the 22nd element of the periodic table belonging to Period 4 and Group 4.

Hence, barium will have smaller first ionization energy.

  • <u>Option 4:</u>

Copper is the 29th element of the periodic table belonging to Period 4 and Group 11.

Silver is the 47th element of the periodic table belonging to Period 5 and Group 11.

Hence, silver will have smaller first ionization energy.

5 0
3 years ago
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