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Dmitriy789 [7]
3 years ago
12

How many grams of sodium make up 4.01×10^25 atoms

Chemistry
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

  • 5.74 ×10 25

Explanation:

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A substance can change into a new kind of molecule when:
Artyom0805 [142]

Answer:

Chemical changes cause a substance to change into an entire substance with a new chemical formula. Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the results are called products.

Hope it helps

4 0
3 years ago
Rank the following from lowest to highest anticipated boiling point: C8H18, CH, C16H34,CH4,C4H10
viva [34]
<span>The relative strength of intermolecular forces such as ionic, hydrogen bonding, dipole-dipole interaction and Vander Waals dispersion force affects the boiling point of a compound. For this case, the longer the chain the higher the boiling point. 

</span>CH, CH4, C4H10, C8H18, C16H34

Hope this answers the question. Have a nice day.
8 0
3 years ago
Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
wolverine [178]

Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,  

= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.  

8 0
4 years ago
An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 151.0 g of water was found to have a
Tasya [4]

ccccccccccccccccccccccccccccccccccc

8 0
4 years ago
What is the overall equation for the covalent bond in H2O . Is it H2 + O2=H2O OR. H2 + O = H2O
AlexFokin [52]

Answer:

The answer is in the photo

Explanation:

I hope that is useful for you :)

4 0
3 years ago
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