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3 years ago

What elements are being reduced and oxidized in this chemical formula?

Chemistry

1 answer:

dangina [55]3 years ago

3 0

Answer: The element Na (Sodium) is getting oxidized and Hydrogen is getting reduced.

Explanation:

Oxidation reactions are the reactions in which addition of oxygen takes place.

Reduction reactions are the reactions in which loss of oxygen takes place.

For a given reaction:

$2Na(s)+2H_2O(l)\rightarrow H_2(g)+2NaOH(aq.)$

Sodium is getting oxidized because there is an addition of reaction with that element.

Hydrogen is getting reduced because there is a removal of oxygen with that element.

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What is the percent composition by mass for sodium (Na) in sodium phosphate (Na3PO4)? % Na = (______/______)x100% = _______% NNA

ozzi

The percent composition by mass for sodium (Na) in Sodium phosphate (Na₃PO₄) : 42.07%

<h3>Further explanation</h3>

Given

Compound of Sodium phosphate (Na₃PO₄)

Required

The percent composition by mass for sodium (Na)

Solution

<em>The Comparative Law (Proust ) : compounds are formed from elements with the same Mass Comparison</em>

MW Na₃PO₄ = 163,94 g/mol

Ar Na=22,989769g/mol

$\tt \%mass~Na=\dfrac{3.Ar~Na}{MW~Na_3PO_4}\times 100\%\\\\\%mass~Na=\dfrac{3\times 22.99}{163.94}\times 100\%\\\\\%mass~Na=42.07\%~Na$

5 0

3 years ago

Pls help!!! I will mark you as brainliest if you answer the question!!

SVEN [57.7K]

1 — Element D and A ( Which are Sodium and aluminium )

2 — ( 2 + 8 + 3 = 13 electrons total ) Element A Because it's atomic number is 13.

3 — Element E Is stable. ( Which is Argon )

( Note, Elements which has 8 election on its outermost cell is stable. ( Helium is exception which is a noble gas but have 2 electrons in outermost cell )

4 — Element F , which is hydrogen. ( Hydrogen is the only element to not have any neutron )

5 — Element D ( Which is sodium )

6 — The element F ( Which is hydrogen ) Don't contain any neutron.

________________________________

5 0

3 years ago

One of the compounds used to increase the octane rating of gasoline is toluene (pictured). suppose 8.30 ml of toluene (d = 0.867

GrogVix [38]

Missing question:<span> How many grams of oxygen are needed for complete combustion of the toluene?
Chemical reaction: </span>C₇H₈ + 9O₂ → 7CO₂ + 4H₂<span>O.
V(</span>C₇H₈) = 8,30 ml.
d(C₇H₈) = 0,867 g/ml.
n(C₇H₈) = V(C₇H₈) · d(C₇H₈).
m(C₇H₈) = 8,3 ml · 0,867 g/ml.
m(C₇H₈) = 7,19 g.
n(C₇H₈) = m(C₇H₈) ÷ M(C₇H₈).
n(C₇H₈) = 7,19 g ÷ 92,14 g/mol = 0,078 mol.
From chemical reaction: n(C₇H₈) : n(O₂) = 1 : 9.
n(O₂) = 9 · 0,078 mol = 0,702 mol.
m(O₂) = 0,702 mol · 32 g/mol = 22,5 g.

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