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andrey2020 [161]
3 years ago
7

What causes leaves to change color in the autumn? Is the change physical or chemical? Explain your answer.

Physics
2 answers:
Svet_ta [14]3 years ago
5 0
The chlorophyll breaks down, the green color<span> disappears, and the yellow to orange</span>colors<span> become visible and give the </span>leaves<span> part of their fall splendor. At the same time other </span>chemical changes<span> may occur, which form additional </span>colors<span> through the development of red anthocyanin pigments.</span>
irinina [24]3 years ago
3 0

Answer  

Leaf color comes from three pigments: chlorophyll, carotenoid, and anthocyanin. Chlorophyll is the pigment that makes leaves green and allows plants to make their own food using sunlight, water, and carbon dioxide. In the autumn, trees stop producing chlorophyll because there is less sunlight available. This allows carotenoid to show through, making the leaves yellow, orange, and brown. This is an example of a chemical change.

Explanation:

this is the exact answer

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Which of the materials would be able to scratch Quartz
Lelechka [254]
<span>anything harder than mohs scale 7 so eg Topaz, Corundum and diamond representing mohs scale 8 9 and 10 respectively.</span>
7 0
3 years ago
Which is the correct Lewis structure for carbon monoxide?<br> А. А<br> В. B<br> С. С<br> D. D
kramer

Answer: Choice B

There are triple bonds between the carbon (C) and oxygen (O) atoms. Then there are 2 dots on either side

==========================================================

Explanation:

When it comes to interaction and chemistry, all that matters is the valence shell or valence electrons. This is the outermost shell. This is because various elements do not interact with the inner electrons (they're locked in place so to speak and don't move to other elements).

Carbon has 6 protons, which is what uniquely makes up this element. This means there are 6 electrons. The inner shell has 2 electrons and the valence shell has 4 electrons. Two electrons are shown as the two blue dots on the left side of the C. The other two electrons form two of the lines, or the bonds, between the C and O.

-------------

Oxygen has 8 protons and 8 electrons. It has 2 electrons in the inner shell and 6 electrons in the valence shell. Two of those electrons are the red dots on the right side of the O. The other 4 electrons are shared to form the bonds with the carbon atom.

This is where things get a bit tricky. I've shown a diagram below indicating that one of the oxygen electrons (red dot) is passed to the carbon, as this carbon atom is pulling on the oxygen electron. But the oxygen atom is pulling on it as well, which forms one of the triple bonds.

So this is why diagram B is the final answer. This is something you can logically determine (remembering the rules of how each electron shell is formed), or it's something you'll need to memorize. In the real world, it's easy to forget a lot of info like this, so that's why having it handy as a lookup reference is preferable.

3 0
3 years ago
Read 2 more answers
HELP When the forces are applied in the same direction, how do you determine net force?
aleksklad [387]

Answer:

Explanation:

If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.

5 0
3 years ago
A permanent magnet is placed near a bar of soft iron PQ what will happen​
boyakko [2]

Answer:

it will rust

Explanation:

hope it helps

4 0
3 years ago
Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The
tia_tia [17]

Answer:

Explanation:

capacitance of sphere 2 will be 4.5 times sphere 1

a ) when spheres are in contact they will have same potential finally . So

V_1 / V_2 = 1

b )

Charge will be distributed in the ratio of their capacity

charge on sphere1 = q  x 1 / ( 1 + 4.5 )

= q / 5.5

fraction = 1 / 5.5

c ) charge on sphere 2

= q x 4.5 / 5.5

fraction = 4.5 / 5.5

d ) surface charge density of sphere 1

= q /( 5.5 x A ) where A is surface area

surface charge density of sphere 2

= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area

= q  /( 5.5 x 4.5 A )

q_1/q_2 = 4.5

6 0
3 years ago
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