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AleksAgata [21]
3 years ago
14

Universal Containers has implemented a strict software architecture for their custom Apex code. One of the requirements is that

all SOQL queries are contained within reusable classes. Depending on the context of the Apex transaction, the queries should be able to run either "With Sharing" or "Without Sharing". Which two ways allow the Architect to meet these requirements.
Computers and Technology
1 answer:
maxonik [38]3 years ago
6 0

Answer:

The required coding for the architect to meet these requirement has been described below.

Explanation:

The following ways will help the architecture to meet the requirement.

Create a reusable SOQLQueries class; specify “With Sharing” on the methods that require user context and “Without Sharing” on the methods requiring system context.

Create a SystemSOQLQueries class and a UserSOQLQueries class; set the “With Sharing” keyword on the UserSOQLQueries class and “Without Sharing” on the SystemSOQLQueries class.

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Option C is correct.

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According to the law of demand, when the supply of one commodity is increased then the demand for other commodity falls. So, the following option  C is correct according to the following scenario.

Other options are incorrect because they are not relevant according to the following scenario.

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The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

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