Photographing during the midday can produce which of the following?

It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.

Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

For optimal 4-way merging, we need one dummy run with size 0.

Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows $L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300$
Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

$L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000$

The resulting run has length 6000 records.

Part b

For step 1

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{I/O per block} is 2 sec

So

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec$

So the input/output time is 46 seconds for step 01.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 2300 for step 01
Size_block is 100 as given
Time_{CPU per block} is 1 sec

So

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec$

So the CPU time is 23 seconds for step 01.

Total time in step 01

$T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\$

Total time in step 01 is 69 seconds.

For step 2

Input Output Time

Input Output Time is given as

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{I/O per block} is 2 sec

So

$T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\, block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec$

So the input/output time is 120 seconds for step 02.

CPU Time

CPU Time is given as

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}$

Here

L_run is 6000 for step 02
Size_block is 100 as given
Time_{CPU per block} is 1 sec

So

$T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\, block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec$

So the CPU time is 60 seconds for step 02.

Total time in step 02

$T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\$

Total time in step 02 is 180 seconds

Merging Time (Total)

Now the total time for merging is given as

$T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\$

Total time in merging is 249 seconds seconds

5 0

3 years ago

NEED ANSWER ASAP. CORRECT ANSWER GETS BRAINLIEST! TY

Tasya [4]

Answer:

scope because the scope will determine the Time for the employee to work

8 0

3 years ago

Wireless networks usually use ____ signals to send data.

barxatty [35]

Wireless networks usually use radio (b) signals to send data.

6 0

3 years ago

Read 2 more answers

Imagine the user types in a complete sentence, but we want to read only the first word and place it in the String variable word.

Vladimir [108]

Answer:

import java.util.Scanner;

public class FirstWord {

public static void main(String[] args) {

//NOW YOU WANT TO COLLECT INPUTS FROM THE STUDENT OR USER

//IMPORT THE SCANNER CLASS FIRST outside your class

// THEN YOU CREATE AN OBJECT OF THE SCANNER CLASS

Scanner input = new Scanner(System.in);

//CREATE A VARIABLE TO HOLD THE USER INPUT

String text = input.nextLine();

//The variable holder will be used to store characters from the for loop

String holder="";

//Create a for loop that loops through the user's input

for(int i=0; i<text.length(); i++){

//As the loop increases, we get the character in the user's input and store them one by one in the variable holder

holder+=text.charAt(i);

if(text.charAt(i)==' '){

//If the loop encounters a space, it means a complete word has been gotten from the user's input

//Then the break below Breaks the loop, and the loop stops running

break;

}

System.out.println(holder);

}

Explanation:

text.length() returns the length of the sequence of characters present in length

text.charAt(a number) Returns the char value at the specified index. An index ranges from 0 to length() - 1. The first char value of the sequence is at index 0, the next at index 1, and so on, as for array indexing.

Create a for loop

How does a for loop work?

It collects a starting point, an end point and an increment respectively....all these are passed in as arguments into the for loop

For example, the code above starts from 0, calculates the number of characters in the user's input and sets it as the end point, the loop runs from zero to the length of the text of the user...

Note: i++ in the loop is the increment, it means the loop increases by 1

8 0

3 years ago

Question 11

STatiana [176]

What type of program would have a class named Student with objects called fullTime and partTime?

A. machine language program

B. object-oriented program

C. markup language program

D. procedural language program

Answer:

B. object-oriented program

Explanation:

An object-oriented program or OOP is a type of program that uses the concepts of objects and methods.

Although they are quite broad, they also make use of classes and types.

Java, for instance makes use of OOP as they use classes and objects under those classes and name them anyhow they want.

Therefore, the correct answer is B

8 0

3 years ago