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ExtremeBDS [4]
3 years ago
15

It doesn't let me post pitures

Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0

Answer:

me neither!

what's wrong with this app?

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2x + y = 20<br> 6x - 5y =12
Vera_Pavlovna [14]
Rearrange the first equation
2x + y = 20
take away 2x from both sides
y = 20 - 2x 
substitute this y value into the second equation
6x - 5(20 - 2x) = 12
6x -100 +10x = 12
add 100 to both sides
6x + 10x = 112
16x = 112
divide both sides by 16 
x = 7
Substitute this x value into the first equation to get y.
2(7) + y = 20
14 + y = 20
take away 14 from both sides
y = 6

So, y = 6 and x = 7
7 0
3 years ago
Read 2 more answers
NEED HELP NOWAngles not necessarily drawn to scale
ahrayia [7]

Answer:

x = 45 degrees

Step-by-step explanation:

Opposite adjacent angles are congruent

160 - x = 115

x = 45

6 0
3 years ago
I NEED HELP ASAP PLEASE PLOT IT
sergejj [24]

So for 1 1/3 you would go to 1 and count 3 lines after that and that is where you would plot it.

and for 2 4/9 you would count 4 lines after 2 but because there is only 6 lines you would divide by 2

6 0
3 years ago
The infinite geometric series S=1+( 2/3 )+( 2/3 )^ 2 +( 2/3 )^ 3 .... equal to:
weqwewe [10]

SOLUTION

The question simply means that we should find the sum to infinity of the geometric series.

The formula of sum to infinity of a geometric serie is given by

S_{\infty}=\frac{a}{1-r}

Where

\begin{gathered} S_{\infty}\text{ is the sum to infinity} \\  \\ a\text{ is the first term = 1} \\  \\ r\text{ is the common ratio = }\frac{2}{3} \end{gathered}

So, this becomes

\begin{gathered} S_{\infty}=\frac{a}{1-r} \\  \\ S_{\infty}=\frac{1}{1-\frac{2}{3}} \\  \\ S_{\infty}=\frac{1}{\frac{3-2}{3}} \\  \\ S_{\infty}=\frac{1}{\frac{1}{3}} \\  \\ S_{\infty}=3 \end{gathered}

Therefore, option b is the correct answer

5 0
1 year ago
Stu trained for a triathlon for 5 hours yesterday. He ran 5 miles and then biked 80 miles. His biking speed is 15 mph faster tha
lara31 [8.8K]

Answer:

Step-by-step explanation:

Given as :

The distance cover while running = D_1 = 5 miles

Let The speed for running = S_1

The distance cover with bike = D_2 = 80 miles

The speed for biking = S_2 = 15 mph +  S_1

Total Time taken = 5 hours

Now Time = \dfrac{\textrm Distance}{\textrm Speed}

∴ 5 hour = \frac{D_1}{S_1} +  \frac{D_2}{S_2}

Or,  5 hour = \frac{5}{S_1} +  \frac{80}{15+S_1}

Or, 5 hour = \frac{75 + 5 S_1 + 80 S_1}{S_1(15+S_1)}

or,  5 × (S_1^{2}+15 S_1) = 85 S_1 + 75

Or, 5 S_1^{2} + 75 S_1 -  85 S_1 - 75 = 0

or, 5 S_1^{2} -10 S_1 - 75 = 0

or,   S_1^{2} -2 S_1 - 15 = 0

Or, S_1^{2} -3 S_1 + 5 S_1- 15 = 0

Or, S_1 (S_1 - 3) + 5 (S_1 - 3) = 0

Or, (S_1 - 3) ( S_1 + 5 ) = 0

∴ S_1 = 3 , - 5

So, the running speed = 3 mile per hour

And the biking speed = 15 mph + 3 mph = 18 mile per hour

Hence The running speed of Stu is 3 mile per hour  .  Answer

7 0
3 years ago
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