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Mamont248 [21]
3 years ago
6

Зn + 14 = -4 What’s the n

Mathematics
2 answers:
larisa86 [58]3 years ago
6 0

<em>so</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>-</em><em>6</em><em>.</em>

<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>

ohaa [14]3 years ago
6 0

Answer:

n = -6

Step-by-step explanation:

<u>Step 1: Subtract 14 from both sides </u>

<u />3n + 14 - 14 = -4 - 14

3n = -18

<u>Step 2: Divide both sides by 3 </u>

<u />3n / 3 = -18 / 3

n = -6

Answer:  n = -6

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Solve for m pls? I'd seriously appreciate it!
Vilka [71]

Answer:

m=-1

Step-by-step explanation:

Start by multiplying both sides by 2, this will get rid of the fraction on the left side and will result in the equation 12m+6=2m-4

Then, subtract 2m from both sides, which leaves the equation as 10m+6=-4

Then, subtract 6 from both sides, this results with the equation 10m=-10

Finally, divide both sides by 10, this will result in m=-1

3 0
3 years ago
Keep the ratio simple.<br> 3/5 : 2/5
fredd [130]

Answer:

3:2

Step-by-step explanation:

I am assuming this means convert to whole numbers

3/5:2/5 is 6/10:4/10

6/10:4/10 is 0.6:0.4

0.6:0.4 is 6:4

6:4 is 3:2

8 0
2 years ago
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Nina [5.8K]

Answer:

Range: 13 and 15        Mean: 247 and 286

Step-by-step explanation:

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3 years ago
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liraira [26]

Answer:

4.5

Step-by-step explanation:

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6 0
2 years ago
On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?
bonufazy [111]

Answer:

Birds F_b=14.3\%

Gerbils F_g=42.9\%

Fish F_f=21.4\%

Hamsters F_h=21.4\%

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds  n_b=2

Number of gerbils  n_g=6

Number of fish  n_f=3

Number of hamsters  n_h=3  

Generally the frequency for birds F_b is mathematically given b

F_b=\frac{n_b}{n}*100

F_b=\frac{2}{14}*100

F_b=14.3\%

Generally the frequency for Gerbils F_g is mathematically given b

F_g=\frac{n_g}{n}*100

F_g=\frac{6}{14}*100

F_g=42.9\%

Generally the frequency for fish F_f is mathematically given b

F_f=\frac{n_f}{n}*100

F_f=\frac{3}{14}*100

F_f=21.4\%

Generally the frequency for fish F_h is mathematically given b

F_h=\frac{n_h}{n}*100

F_h=\frac{3}{14}*100

F_h=21.4\%

5 0
3 years ago
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