In the fist you have to know: a<span>ny angle opposite the head is equal in measurement.
so now we know o</span><span>ne angle in the triangle it is 82
</span><span>All corners of the triangle are equal 180
</span>so we have to do this 180-82=98
so we have to collection (4x+8)+(8x-6)=98
12x+2=98
12x=96
x=8
4(8)+8=40
the answer is 40
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The result of the product of (0.36) and (0.53) is 0.1908
<h3>How to determine the product</h3>
The product expression is given as:
(0.36) * (0.53)
Rewrite the product as follows:
Expand the product
Expand
Evaluate the sum
See attachment for the area diagram of the product
Read more about products at:
brainly.com/question/10873737
Answer:
horizontal and vertical
Step-by-step explanation:
if its the plus?
So 2 gallons every 5 minutes
2/5= .4
so .4 a minute
and you already have 5 gallons in so those need to be added
m=minutes
y=0.4m + 5 will be what you want to find out if you are looking to find out how much will be there in a certain time
for 50 minutes you will have
y=0.4(50) +5
20+5
25 gallons
HOWEVER, the equation has to be changed if you want to tell how long you have to wait for it to fill.
m=2.5(g-5)
m=minutes
g= gallons
you subtract 5 because they are already there
you multiply by 2.5 because it fills at a rate of 1 gallon every 2.5 minutes.
m=2.5(1500-5)
for the sake of it being easier i will do the -5 separately
2.5(1500 = 3750
2.5(-5= -12.5
3750-12.5
3737.5 minutes to fill the pool.
3720/60 = 62
17.5/60 = .292
62.292 hours to fill the pool.
p.s. you have a really slow hose.
Its good you didn't wait for it to fill, you would have died from lack of water before then if you just sat and waited.
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Answer:
D. The graph of function 
is the graph of function 
shifted 4 units to the left.
Step-by-step explanation:
the function is composite function between and 
, then you can re-write as:
The transformation happened in the input, then you have an horizontal shifted and how it's adding 4 units then you go "faster" and move to left the graph.
In the image you can see what's mean sum a constant in the 
of a function.
